请各位大神支招
由 tony_lei 发布于 2014年12月07日无人欣赏。
早上起来看了下邮件又被拒了。
14.3: Apps that display user generated content must include a method for filtering objectionable material, a mechanism for users to flag offensive content, and the ability to block abusive users from the service
之前被这个拒过一次，然后我们就在后台添加了关键字过滤的功能，即写一个敏感词过滤的程序，每5分钟跑一次，以为这样就ok了，但还能通过。 单从被拒字面上理解是添加过滤和举报的功能，请问这个我们要怎么做？我们是一个做服装搭配的app，用户可以上传照片产生内容，图片展示类似于花瓣，我看了下花瓣（已经上appstore），也没有在页面上做类似的过滤或者举报的功能。求大神支招
被拒的话，两个问题：
- 要贴你自己的东西和全部被拒文档
- 确保自己有英文阅读能力，且通读被拒文档（没有流畅阅读能力，至少也可以在字典的帮助下通读）。否则就是浪费自己和大家的时间。
花瓣写过一个多次被拒的上线经过，你可以找来参考。但是简单的说，我认为他们多次被拒多半有点活该，不知道怎么阅读被拒文档和怎么合理的用英文回复，是大多数被拒以后应对失败的原因
谢谢tinyfool的回复，完整的内容如下。苹果拒绝的理由里面提到，要把下面提到的几点注意事项放在指定位置，请问这个指定位置是哪里？也没有类似的app的做法提供一下参考的？
Reasons
14.3: Apps that display user generated content must include a method for filtering objectionable material, a mechanism for users to flag offensive content, and the ability to block abusive users from the service
----- 14.3 -----
Also, your app enables the display of user-generated content but does not have the recommended precautions in place, as required by the App Store Review Guidelines.
It is necessary that you put all of the following precautions in place:
- Require that users agree to terms (EULA) and these terms must make it clear that there is no tolerance for objectionable content
- Use moderators to flag and remove inappropriate content and offensive users
- Users need a mechanism to flag objectionable content and report users generating this content
- Developer must act on objectionable content reports within 24 hours by removing the content and ejecting the user who provided the offending content
- Developer needs a method for ejecting users who violate the terms of the EULA